题目内容
分解因式:
(1)y2-y+
.
(2)4x2-20x+25.
(3)-4a2b+12ab2-9b3.
(4)(a-b)2-2(a-b)+1.
(1)y2-y+
| 1 |
| 4 |
(2)4x2-20x+25.
(3)-4a2b+12ab2-9b3.
(4)(a-b)2-2(a-b)+1.
(1)原式=(y-
)2;
(2)原式=(2x-5)2;
(3)原式=-b(4a2-12ab+9b2)=-b(2a-3b)2;
(4)原式=(a-b-1)2.
| 1 |
| 2 |
(2)原式=(2x-5)2;
(3)原式=-b(4a2-12ab+9b2)=-b(2a-3b)2;
(4)原式=(a-b-1)2.
练习册系列答案
相关题目