题目内容
分解因式:x4-5x2+4x=______.
x4-5x2+4x
=x(x3-x-4x+4)
=x[x(x2-1)-4(x-1)]
=x[x(x-1)(x+1)-4(x-1)]
=x(x-1)(x2+x-4)
=x(x-1)(x-
)(x-
).
故答案为:x(x-1)(x-
)(x-
).
=x(x3-x-4x+4)
=x[x(x2-1)-4(x-1)]
=x[x(x-1)(x+1)-4(x-1)]
=x(x-1)(x2+x-4)
=x(x-1)(x-
-1+
| ||
| 2 |
-1-
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| 2 |
故答案为:x(x-1)(x-
-1+
| ||
| 2 |
-1-
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| 2 |
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