题目内容
（1）计算：2-2+|-
|-(π-2013)0；
（2）化简：(
-
)÷
．
| 1 |
| 4 |
（2）化简：(
| 1 |
| 2 |
| a |
| 2a+2 |
| a |
| a+1 |
（1）2-2+|-
|-(π-2013)0
=
+
-1
=-
；
（2）(
-
)÷
=
×
-
×
=
-
=
-
=
．
| 1 |
| 4 |
=
| 1 |
| 4 |
| 1 |
| 4 |
=-
| 1 |
| 2 |
（2）(
| 1 |
| 2 |
| a |
| 2a+2 |
| a |
| a+1 |
=
| 1 |
| 2 |
| a+1 |
| a |
| a |
| 2(a+1) |
| a+1 |
| a |
=
| a+1 |
| 2a |
| 1 |
| 2 |
=
| a+1 |
| 2a |
| a |
| 2a |
=
| 1 |
| 2a |
练习册系列答案
阅读快车系列答案
相关题目
