题目内容
先化简,后求值:| 1 |
| -x+1 |
| 1 |
| -x2+1 |
| x-1 |
| x2-2x+1 |
| 3 |
分析:先计算除法运算,计算时分子分母能分解因式的先分解因式再约分,然后计算减法运算,最后代入.
解答:解:原式=
+
×
=
+
×
=
+
=
,
当x=-
时,
原式=
=
=-1.
| 1 |
| -x+1 |
| 1 |
| x2-1 |
| x2-2x+1 |
| x-1 |
=
| 1 |
| 1-x |
| 1 |
| (x+1)(x-1) |
| (x-1)2 |
| x-1 |
=
| 1 |
| 1-x |
| 1 |
| 1+x |
=
| 2 |
| 1-x2 |
当x=-
| 3 |
原式=
| 2 | ||
1-(-
|
| 2 |
| -2 |
点评:本题是一道基础题,先将分式约分、通分,代值计算即可.
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