题目内容
先化简,再求值:(1)
| x-1 |
| x |
| 1 |
| x |
(2)(
| 1 |
| x-y |
| 1 |
| x+y |
| xy |
| x2-y2 |
| 3 |
| 2 |
| 2 |
分析:先把括号里式子通分,再把除法转化为乘法,约分化为最简,最后代值计算.
解答:解:(1)原式=
÷
=
•
=
;
当x=3时,原式=
.
(2)原式=
•
=
;
当x=
-
,y=
时,原式=
=
.
| x-1 |
| x |
| x2-1 |
| x |
=
| x-1 |
| x |
| x |
| (x+1)(x-1) |
=
| 1 |
| x+1 |
当x=3时,原式=
| 1 |
| 4 |
(2)原式=
| 2x |
| x2-y2 |
| x2-y2 |
| xy |
| 2 |
| y |
当x=
| 3 |
| 2 |
| 2 |
| 2 | ||
|
| 2 |
点评:本题主要考查分式的化简求值这一知识点,把分式化到最简是解答的关键.
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