题目内容
化简求值:2(x2y+xy)-3(x2y-xy+1)-4xy,其中x=
,y=-1.
| 1 | 2 |
分析:先去括号,然后合并同类项,再将x=
,y=-1分别代入化简后的式子即可解答.
| 1 |
| 2 |
解答:解:2(x2y+xy)-3(x2y-xy+1)-4xy
=2x2y+2xy-3x2y+3xy-3-4xy
=-x2y+xy-3,
当x=
, y=-1时,
原式=-(
)2×(-1)+
×(-1)-3
=
-
-3
=-3
.
=2x2y+2xy-3x2y+3xy-3-4xy
=-x2y+xy-3,
当x=
| 1 |
| 2 |
原式=-(
| 1 |
| 2 |
| 1 |
| 2 |
=
| 1 |
| 4 |
| 1 |
| 2 |
=-3
| 1 |
| 4 |
点评:本题考查了整式的加减--化简求值,明确去括号法则及合并同类项法则是解题的关键.
练习册系列答案
相关题目