题目内容
化简:(| x |
| x+1 |
| 1 |
| x-1 |
| 1 |
| x2-1 |
分析:先通分再进行分式的混合运算即可.
解答:解:原式=[
+
]×(x+1)(x-1)
=x(x-1)+x+1
=x2-x+x+1
=x2+1.
| x(x-1) |
| (x+1)(x-1) |
| x+1 |
| (x+1)(x-1) |
=x(x-1)+x+1
=x2-x+x+1
=x2+1.
点评:本题考查了分式的混合运算,是基础知识要熟练掌握.
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