题目内容
若
=
=
,则
=
| a |
| 2 |
| b |
| 3 |
| c |
| 4 |
| 3a-2b+5c |
| -6a-b-3c |
-
| 20 |
| 27 |
-
.| 20 |
| 27 |
分析:设
=
=
=k,求出a=2k,b=3k,c=4k,把a、b、c的值代入,即可求出答案.
| a |
| 2 |
| b |
| 3 |
| c |
| 4 |
解答:解:设
=
=
=k,
则a=2k,b=3k,c=4k,
∴
=
=-
.
故答案为:-
.
| a |
| 2 |
| b |
| 3 |
| c |
| 4 |
则a=2k,b=3k,c=4k,
∴
| 3a-2b+5c |
| -6a-b-3c |
=
| 3×2k-2×3k+5×4k |
| -6×2k-3k-3×4k |
=-
| 20 |
| 27 |
故答案为:-
| 20 |
| 27 |
点评:本题考查了比例的性质的应用,主要考查学生能否选择适当的方法进行代入,注意:设
=
=
=k,求出a=2k,b=3k,c=4k,再进行代入即可.
| a |
| 2 |
| b |
| 3 |
| c |
| 4 |
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=
=
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