题目内容
计算或化简
(1)(-3)+(-4)-(+11)-(-9);
(2)(
-
-
)×(-60);
(3))23÷[(-3)3-(-4)];
(4)-14÷(-5)2×(-
)+|0.8-1|.
(5)2a3b-
a3b-a2b+
a2b-ab2
(6)2(2a2+9b)+3(-5a2-4b)
(1)(-3)+(-4)-(+11)-(-9);
(2)(
| 2 |
| 3 |
| 1 |
| 12 |
| 1 |
| 15 |
(3))23÷[(-3)3-(-4)];
(4)-14÷(-5)2×(-
| 5 |
| 3 |
(5)2a3b-
| 1 |
| 2 |
| 1 |
| 2 |
(6)2(2a2+9b)+3(-5a2-4b)
分析:(1)先去括号,再从左到右依次计算即可;
(2)根据乘法分配律进行计算即可;
(3)先算括号里面的,再算除法即可;
(4)先算乘方,再算乘除,最后算加减;
(5)直接合并同类项即可;
(6)先去括号,再合并同类项即可.
(2)根据乘法分配律进行计算即可;
(3)先算括号里面的,再算除法即可;
(4)先算乘方,再算乘除,最后算加减;
(5)直接合并同类项即可;
(6)先去括号,再合并同类项即可.
解答:解:(1)原式=-3-4-11+9
=-7-11+9
=-18+9
=-9;
(2)原式=
×(-60)-
×(-60)-
×(-60)
=-40+5+4
=-31;
(3)原式=23÷[-27+4]
=23÷(-23)
=-1;
(4)原式=-1÷25×(-
)+0.2
=-
×(-
)+0.2
=
+0.2
=
;
(5)原式=(2-
)a3b-(1-
)a2b-ab2
=
a3b-
a2b-ab2;
(6)原式=4a2+18b-15a2-12b
=-11a2+6b.
=-7-11+9
=-18+9
=-9;
(2)原式=
| 2 |
| 3 |
| 1 |
| 12 |
| 1 |
| 15 |
=-40+5+4
=-31;
(3)原式=23÷[-27+4]
=23÷(-23)
=-1;
(4)原式=-1÷25×(-
| 5 |
| 3 |
=-
| 1 |
| 25 |
| 5 |
| 3 |
=
| 1 |
| 15 |
=
| 4 |
| 15 |
(5)原式=(2-
| 1 |
| 2 |
| 1 |
| 2 |
=
| 3 |
| 2 |
| 1 |
| 2 |
(6)原式=4a2+18b-15a2-12b
=-11a2+6b.
点评:本题考查的是整式的加减及有理数的混合运算,熟知整式的加减实质上是合并同类项是解答此题的关键.
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