题目内容
先化简,再求值:
-
÷
,其中x=
.
| 1 |
| x-1 |
| 4x-4 |
| x2-1 |
| 4x |
| x+1 |
| 1 |
| 2 |
分析:先分子和分母因式分解以及除法运算转化为乘法运算得到原式=
-
•
,约分后得到
-
,然后进行通分,接着把x的值代入进行计算.
| 1 |
| x-1 |
| 4(x-1) |
| (x+1)(x-1) |
| x+1 |
| 4x |
| 1 |
| x-1 |
| 1 |
| x |
解答:解:原式=
-
•
=
-
=
=
.
当x=
时,原式=
=-4.
| 1 |
| x-1 |
| 4(x-1) |
| (x+1)(x-1) |
| x+1 |
| 4x |
=
| 1 |
| x-1 |
| 1 |
| x |
=
| x-(x-1) |
| x(x-1) |
=
| 1 |
| x2-x |
当x=
| 1 |
| 2 |
| 1 | ||||
(
|
点评:本题考查了分式的化简求值:先把各分子或分母因式分解,再进行乘除运算(除法运算转化为乘法运算),然后进行加减运算,最后把满足条件的字母的值代入进行计算求值.
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