题目内容
计算:(1)(+9)-(+10)+(-2)-(-8)+3(2)(-4
| 7 |
| 9 |
| 1 |
| 6 |
| 2 |
| 9 |
| 1 |
| 6 |
(3)-10×3×(-
| 3 |
| 5 |
| 1 |
| 3 |
(4)-2-12×(
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
(5)-4+16-(-2)-(-25)×(-6)
(6)(-2
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 11 |
分析:(1)(2)运用有理数的加减法则进行计算即可;
(3)(4)(5)(6)先根据有理数的乘法法则计算乘法,再根据有理数的加减法则进行加减即可.
(3)(4)(5)(6)先根据有理数的乘法法则计算乘法,再根据有理数的加减法则进行加减即可.
解答:解:(1)原式=(+9)+(-10)+(-2)+(+8)+3=9-10-2+8+3=8;
(2)原式=(-4
)+(+3
)+(-2
)+(-6
),
=-4
+3
-2
-6
,
=-7-3=-10;
(3)原式=-10×3×
×
=-6;
(4)原式=-2-(4-3+6)=-2-7=-9;
(5)原式=-4+16+2-150=-136;
(6)原式=-16-
-
=-16
.
(2)原式=(-4
| 7 |
| 9 |
| 1 |
| 6 |
| 2 |
| 9 |
| 1 |
| 6 |
=-4
| 7 |
| 9 |
| 1 |
| 6 |
| 2 |
| 9 |
| 1 |
| 6 |
=-7-3=-10;
(3)原式=-10×3×
| 3 |
| 5 |
| 1 |
| 3 |
(4)原式=-2-(4-3+6)=-2-7=-9;
(5)原式=-4+16+2-150=-136;
(6)原式=-16-
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
点评:本题考查了有理数的加减、乘法的应用,能熟练地进行计算是解此题的关键.
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