题目内容
| a+2 |
| a-2 |
| a-2 |
| a+2 |
| 8a |
| a2-4 |
0
0
.分析:先通分,再把分子相加减即可.
解答:解:原式=
-
-
=
=
=0.
故答案为:0.
| (a+2)2 |
| (a+2)(a-2) |
| (a-2)2 |
| (a+2)(a-2) |
| 8a |
| (a+2)(a-2) |
=
| a2+4+4a-a2-4+4a-8a |
| (a+2)(a-2) |
=
| 0 |
| (a+2)(a-2) |
=0.
故答案为:0.
点评:本题考查的是分式的加减法,再解答此类题目时要注意通分及约分的灵活应用.
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