题目内容
先化简,再求值:(| x+1 |
| x-1 |
| 1 |
| x2-2x+1 |
| x |
| x-1 |
| 2 |
分析:先通分,然后进行四则运算,最后将x=
代入即可得出答案.
| 2 |
解答:解:原式=
×
=
×
=
将x=
代入原式=
=2+
.
| (x-1)(x+1)+1 |
| (x-1)2 |
| x-1 |
| x |
| x2 |
| (x-1)2 |
| x-1 |
| x |
| x |
| x-1 |
将x=
| 2 |
| ||
|
| 2 |
点评:本题主要考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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