题目内容
19、计算:an-5(an+1b3m-2)2+(an-1bm-2)3(-b3m+2)
分析:先利用积的乘方,去掉括号,再利用同底数幂的乘法计算,最后合并同类项即可.
解答:解:原式=an-5(a2n+2b6m-4)+a3n-3b3m-6(-b3m+2),
=a3n-3b6m-4+a3n-3(-b6m-4),
=a3n-3b6m-4-a3n-3b6m-4,
=0.
=a3n-3b6m-4+a3n-3(-b6m-4),
=a3n-3b6m-4-a3n-3b6m-4,
=0.
点评:本题考查了合并同类项,同底数幂的乘法,幂的乘方,积的乘方,理清指数的变化是解题的关键.
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