题目内容
单项式3x2y,-x2y,
x2y的和是
x2y.
x2y..
| 3 |
| 4 |
| 11 |
| 4 |
| 11 |
| 4 |
分析:根据合并同类项得到3x2y+(-x2y)+
x2y=(3-1+
)x2y=
x2y.
| 3 |
| 4 |
| 3 |
| 4 |
| 11 |
| 4 |
解答:解:3x2y+(-x2y)+
x2y=(3-1+
)x2y=
x2y.
故答案为
x2y.
| 3 |
| 4 |
| 3 |
| 4 |
| 11 |
| 4 |
故答案为
| 11 |
| 4 |
点评:本题考查了合并同类项:合并同类项是把同类项的系数相加减,字母和字母的指数不变.
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