题目内容
先化简,再求值:| 1+x |
| 1-x |
| 2x |
| 1-x |
| 2 |
分析:本题的关键是正确进行分式的通分、约分,并准确代值计算.
解答:解:原式=
÷
=
÷
=
•
=-
,
当x=
时,原式=-
=-
=-
.
| 1+x |
| 1-x |
| x-x2-2x |
| 1-x |
=
| 1+x |
| 1-x |
| -x(x+1) |
| 1-x |
=
| 1+x |
| 1-x |
| 1-x |
| -x(x+1) |
=-
| 1 |
| x |
当x=
| 2 |
| 1 |
| x |
| 1 | ||
|
| ||
| 2 |
点评:首先把分式化到最简,然后代值计算.
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