题目内容
(1)化简:
÷(y+2-
)
(2)计算:(
+
)÷
.
| y-3 |
| 4y-8 |
| 5 |
| y-2 |
(2)计算:(
| a+2 |
| a2-2a |
| 8 |
| 4-a2 |
| a-2 |
| a |
分析:(1)先算括号里的,再算括号外的;
(2)先算括号里的,再算括号外的.
(2)先算括号里的,再算括号外的.
解答:解:(1)原式=
×
=
;
(2)原式=
×
=
.
| y-3 |
| 4y-8 |
| y-2 |
| (y+3)(y-3) |
| 1 |
| 4y+12 |
(2)原式=
| (a-2)2 |
| a(a+2)(a-2) |
| a |
| a-2 |
| 1 |
| a+2 |
点评:本题考查了分式的混合运算,解题的关键是注意通分和约分,以及乘除法的转化.
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