题目内容
计算:
(1)x(2-
)+
•(x2-4);
(2)
+
.
(1)x(2-
| 1 |
| x |
| x |
| x2-2x |
(2)
| 1 |
| 1+x |
| 2x |
| 1-x2 |
分析:(1)先计算括号里的,再合并同类项即可;
(2)通分后,再计算即可.
(2)通分后,再计算即可.
解答:解:(1)原式=x•
+
•(x+2)(x-2)
=2x-1+x+2
=3x+1;
(2)原式=
=
.
| 2x-1 |
| x |
| x |
| x(x-2) |
=2x-1+x+2
=3x+1;
(2)原式=
| 1-x+2x |
| (1-x)(1+x) |
=
| 1 |
| 1-x |
点评:本题考查了分式的混合运算,解题的关键是注意通分和约分.
练习册系列答案
相关题目