题目内容
化简:(1)(12a3b2-8a2b3)÷4ab (2)
•
| a2-2a |
| a+4 |
| a2+8a+16 |
| 4a2-8a |
(1)原式=12a3b2÷4ab-8a2b3÷4ab=3a2b-2ab2;
(2)原式=
•
=
.
(2)原式=
| a(a-2) |
| a+4 |
| (a+4)2 |
| 4a(a-2) |
| a+4 |
| 4 |
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