题目内容
先化简,再求值:
÷
,其中x=2,y=-1.
| y(x-y)-x(x+y) |
| x2-y2 |
| x2+y2 |
| x+y |
分析:将原式y(x-y)-x(x+y)因式分解,x2-y2因式分解,约分后将x=2,y=-1代入分式即可.
解答:解:原式=
•
=-
•
=-
,
将x=2,y=-1代入=-
,
原式=-
=-
.
| xy-y2-x2-xy |
| (x-y)(x+y) |
| x+y |
| x2+y2 |
=-
| y2+x2 |
| (x-y)(x+y) |
| x+y |
| x2+y2 |
=-
| 1 |
| x-y |
将x=2,y=-1代入=-
| 1 |
| x-y |
原式=-
| 1 |
| 2+1 |
| 1 |
| 3 |
点评:本题考查了分式的化简求值,会因式分解和约分是解题的关键.
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