题目内容
对于非零实数x,y,z,设
=
=
=t,那么t的值( )
| x+y-z |
| z |
| x-y+z |
| y |
| -x+y+z |
| x |
| A、必定是1 |
| B、可以是±1 |
| C、可以是1或-2 |
| D、将随x,y,z而变化 |
分析:此题应考虑两种情况:当x+y+z≠0时,根据等比性质求解;当x+y+z=0时,从中导出x+y=-z,代入即可求解.
解答:解:当x+y+z≠0时,则有t=
=1;
当x+y+z=0时,则有x+y=-z,即t=
=-2.
故选C.
| x+y+z |
| x+y+z |
当x+y+z=0时,则有x+y=-z,即t=
| -2z |
| z |
故选C.
点评:此题主要是等比性质的运用:若
=
=…=
=k,则
=k(b+d+…+n≠0).
| a |
| b |
| c |
| d |
| m |
| n |
| a+c+…+m |
| b+d+…+n |
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