题目内容
已知:| x |
| 3 |
| y |
| 4 |
| z |
| 5 |
| x+y+z |
| x |
分析:首先根据题意即可设
=
=
=k,即可求得x,y,z的值,代入
,即可求得答案.
| x |
| 3 |
| y |
| 4 |
| z |
| 5 |
| x+y+z |
| x |
解答:解:设
=
=
=k,
∴x=3k,y=4k,z=5k,
∴
=
=4.
| x |
| 3 |
| y |
| 4 |
| z |
| 5 |
∴x=3k,y=4k,z=5k,
∴
| x+y+z |
| x |
| 3k+4k+5k |
| 3k |
点评:此题考查了比例的性质.此题难度不大,解题的关键是根据题意设
=
=
=k,然后求得x,y,z的值.
| x |
| 3 |
| y |
| 4 |
| z |
| 5 |
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