题目内容
计算题:(1)2
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
(2)(-2)÷
| 1 |
| 3 |
(3)-2
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 2 |
| 3 |
| 11 |
| 1 |
| 4 |
(4)(
| 1 |
| 3 |
| 1 |
| 6 |
| 7 |
| 12 |
| 1 |
| 6 |
(5)2
| 1 |
| 6 |
| 1 |
| 6 |
| 13 |
| 6 |
(6)-32-[-
| 1 |
| 3 |
| 3 |
| 5 |
分析:(1)先把小数化为分数,再结合同分母的数;
(2)先乘方,后乘除,最后加减;
(3)先算括号里的,再按从左到右的顺序计算;
(4)先把除法转化为乘法,再按乘法分配律计算;
(5)按乘法分配律的逆运算计算;
(6)先乘方,后乘除,有括号先算括号里的.
(2)先乘方,后乘除,最后加减;
(3)先算括号里的,再按从左到右的顺序计算;
(4)先把除法转化为乘法,再按乘法分配律计算;
(5)按乘法分配律的逆运算计算;
(6)先乘方,后乘除,有括号先算括号里的.
解答:解:(1)原式=2
+
+7
-2
-1
-2
=2
-2
+
-2
+7
-1
=-2+6
=4;
(2)原式=-2×3×(-3)-5-1
=18-5-1
=12;
(3)原式=-
×(-
)×
×
=
×
×
×
=
;
(4)原式=(
-3+
-
)×(-6)
=-2+8-1+
=15+3
=18
;
(5)原式=
×5+
×4-
×8
=
×(5+4-8)
=
×1=
;
(6)原式=-9-[-
-(1-
×
)×9]
=-9-(-
-
×9)
=-9-(-
-6)
=-9-(-6
)
=-2
.
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
=2
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
=-2+6
=4;
(2)原式=-2×3×(-3)-5-1
=18-5-1
=12;
(3)原式=-
| 11 |
| 5 |
| 1 |
| 6 |
| 3 |
| 11 |
| 4 |
| 5 |
=
| 11 |
| 5 |
| 1 |
| 6 |
| 3 |
| 11 |
| 4 |
| 5 |
=
| 2 |
| 25 |
(4)原式=(
| 1 |
| 3 |
| 1 |
| 6 |
| 7 |
| 12 |
=-2+8-1+
| 7 |
| 2 |
=15+3
| 1 |
| 2 |
=18
| 1 |
| 2 |
(5)原式=
| 13 |
| 6 |
| 13 |
| 6 |
| 13 |
| 6 |
=
| 13 |
| 6 |
=
| 13 |
| 6 |
| 13 |
| 6 |
(6)原式=-9-[-
| 1 |
| 3 |
| 1 |
| 5 |
| 5 |
| 3 |
=-9-(-
| 1 |
| 3 |
| 2 |
| 3 |
=-9-(-
| 1 |
| 3 |
=-9-(-6
| 1 |
| 3 |
=-2
| 2 |
| 3 |
点评:本题考查的是有理数的混合运算的能力,要注意运算顺序及符号的处理,灵活应用运算律可使计算简便.
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