题目内容
(1)计算:22-(| 3 |
| 1 |
| 2 |
(2)先化简,再求值:
| a3 |
| a+1 |
| a |
| a+1 |
| 5 |
分析:(1)根据有理数的乘方、零指数幂和负整数指数幂等知识点进行解答,
(2)首先把分式进行通分,然后分解因式,约分,最后代值计算.
(2)首先把分式进行通分,然后分解因式,约分,最后代值计算.
解答:解:(1)原式=4-1+2=5;
(2)原式=
=
=a(a-1)
=a2-a,
当=
时原式=(
)2-
=5-
.
故答案为5、5-
.
(2)原式=
| a3-a |
| a+1 |
=
| a(a+1)(a-1) |
| a+1 |
=a(a-1)
=a2-a,
当=
| 5 |
| 5 |
| 5 |
| 5 |
故答案为5、5-
| 5 |
点评:本题主要考查负整数指数幂和零指数幂及分式化简求值等知识点.
练习册系列答案
相关题目