题目内容
先化简,再求值:-8xy2+3xy-2(xy2-xy),其中x=
,y=-2.
| 1 |
| 5 |
-8xy2+3xy-2(xy2-xy)
=-8xy2+3xy-2xy2+2xy
=-10xy2+5xy.
当x=
,y=-2时,
原式=-10xy2+5xy
=-10×
×(-2)2+5×
×(-2)
=-8-2
=-10.
=-8xy2+3xy-2xy2+2xy
=-10xy2+5xy.
当x=
| 1 |
| 5 |
原式=-10xy2+5xy
=-10×
| 1 |
| 5 |
| 1 |
| 5 |
=-8-2
=-10.
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