题目内容
先化简,再求值:x(x+y)-(x-y)(x+y)-y2,其中x=0.252008,y=42008.
【答案】分析:本题需先把所要求的式子根据整式的运算顺序进行化简,再根据x、y的值代入即可求出结果.
解答:解:x(x+y)-(x-y)(x+y)-y2,
=x(x+y)-(x-y)(x+y)-y2,
=x2+xy-(x2-y2)-y2,
=x2+xy-x2+y2-y2,
=xy.
当x=0.252008,y=42008时,
原式=(0.25×4)2008,
=1.
点评:本题主要考查了整式的混合运算-化简求值,在解题时要根据整式的运算顺序画到最简,再把得数代入是本题的关键.
解答:解:x(x+y)-(x-y)(x+y)-y2,
=x(x+y)-(x-y)(x+y)-y2,
=x2+xy-(x2-y2)-y2,
=x2+xy-x2+y2-y2,
=xy.
当x=0.252008,y=42008时,
原式=(0.25×4)2008,
=1.
点评:本题主要考查了整式的混合运算-化简求值,在解题时要根据整式的运算顺序画到最简,再把得数代入是本题的关键.
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