题目内容
计算:
(1)
•
;
(2)
-
;
(3)
-
•(
-x-y).
(1)
| x-2 |
| x+3 |
| x2-9 |
| x2-4 |
(2)
| 3 |
| x-4 |
| 24 |
| x2-16 |
(3)
| 1 |
| 2x |
| 1 |
| x+y |
| x+y |
| 2x |
分析:(1)直接根据分式的乘法法则进行计算即可;
(2)先通分,再把分子相加减即可;
(3)先所括号里面的,再算乘法,最后算加减即可.
(2)先通分,再把分子相加减即可;
(3)先所括号里面的,再算乘法,最后算加减即可.
解答:解:(1)原式=
•
=
;
(2)原式=
-
=
=
=
;
(3)原式=
-
•
=
-
=
=1.
| x-2 |
| x+3 |
| (x+3)(x-3) |
| (x+2)(x-2) |
=
| x-3 |
| x+2 |
(2)原式=
| 3 |
| x-4 |
| 24 |
| (x+4)(x-4) |
=
| 3(x+4)-24 |
| (x+4)(x-4) |
=
| 3x-12 |
| (x+4)(x-4) |
=
| 3 |
| x+4 |
(3)原式=
| 1 |
| 2x |
| 1 |
| x+y |
| (x+y)(1-2x) |
| 2x |
=
| 1 |
| 2x |
| 1-2x |
| 2x |
=
| 1-1+2x |
| 2x |
=1.
点评:本题考查的是分式的混合运算,在解答此类题目时要注意通分及约分的灵活应用.
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