题目内容
计算:(x+1 |
x-1 |
1 |
x2-2x+1 |
x2 |
x-1 |
分析:括号里的最简公分母为(x-1)2,化简后把除法统一为乘法,化简即可.
解答:解:原式=[
+
]•
=
•
=
.
故答案为
.
(x+1)(x-1) |
(x-1)2 |
1 |
(x-1)2 |
x-1 |
x2 |
=
x2 |
(x-1)2 |
x-1 |
x2 |
=
1 |
x-1 |
故答案为
1 |
x-1 |
点评:本题主要考查分式的混合运算,解答本题关键是通分和约分,注意把除法运算转化成乘法运算.
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