题目内容
先化简,再求值:
(1)2x3+4x-
x2-(x+3x2-2x3),其中x=-3;
(2)
x-2(x-
y2)+(-
x+
y2),其中x=-2,y=
.
(1)2x3+4x-
| 1 |
| 3 |
(2)
| 1 |
| 2 |
| 1 |
| 3 |
| 3 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
(1)原式=2x3+4x-
x2-x-3x2+2x3=4x3-
x2+3x,
当x=-3时,原式=4×(-27)-
×9+3×(-3)=-147;
(2)原式=
x-2x+
y2-
x+
y2=y2-3x,
当x=-2,y=
时,原式=
.
| 1 |
| 3 |
| 10 |
| 3 |
当x=-3时,原式=4×(-27)-
| 10 |
| 3 |
(2)原式=
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 1 |
| 3 |
当x=-2,y=
| 2 |
| 3 |
| 58 |
| 9 |
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