题目内容
先化简,再求值:(| x+2 |
| x2-2x |
| x |
| x-2 |
| x-1 |
| x |
| 1 |
| 2 |
分析:对(
-
)÷
,将括号内通分、分解因式转化为
,将÷
转化为×
,化简为-
将x=
代入化简后分式求解.
| x+2 |
| x2-2x |
| x |
| x-2 |
| x-1 |
| x |
| -(x-2)(x+1) |
| x(x -2) |
| x-1 |
| x |
| x |
| x-1 |
| x+1 |
| x-1 |
将x=
| 1 |
| 2 |
解答:解:原式=
×
,
=
×
,
=-
,
当x=
,原式=-
=3.
| x+2-x2 |
| x(x -2) |
| x |
| x-1 |
=
| -(x-2)(x+1) |
| x(x -2) |
| x |
| x-1 |
=-
| x+1 |
| x-1 |
当x=
| 1 |
| 2 |
| ||
|
点评:解答此题的关键是把分式化到最简,然后代值计算.
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