题目内容
先化简,再求值:(| x |
| x-2 |
| x |
| x+2 |
| 4x |
| x-2 |
分析:先通分,然后进行四则运算,最后将x=2005代入.
解答:解:原式=
•
=
=
.
| x2+2x-x2+2x |
| (x+2)(x-2) |
| x-2 |
| 4x |
=
| 1 |
| x+2 |
=
| 1 |
| 2007 |
点评:解答此题的关键是把分式化到最简,然后代值计算.
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题目内容
先化简,再求值:(| x |
| x-2 |
| x |
| x+2 |
| 4x |
| x-2 |
| x2+2x-x2+2x |
| (x+2)(x-2) |
| x-2 |
| 4x |
| 1 |
| x+2 |
| 1 |
| 2007 |