题目内容

A

解:(1)解方程组:

得:                                                ……3分

∴A(-1,0),B(0,2)                                     ……4分

(2)不发生变化.                                                    ……5分

     ∠P=180°-∠PAB-∠PBA

        =180°-(∠EAB+∠FBA)                                 ……6分

        =180°-(∠ABO+90°+∠BAO+90°)                     ……7分

        =180°-(180°+180°-90°)

        =180°-135°

        =45°                                                      ……8分

(3)作GM⊥BF于点M                                                ……9分

由已知有:∠AGH=90°-∠EAC

                  =90°-(180°-∠BAC)

∠BAC                                         ……10分

             ∠BGC=∠BGM-∠BGC

                  =90°-∠ABC-(90°-∠ACF)

                  =(∠ACF-∠ABC)

                  =∠BAC                                         ……11分

∴∠AGH=∠BGC                                         ……12分

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