题目内容
计算
(1)(a+b)-4(2a-3b)+(3a-2b)
(2)(
a4b7+
a3b8-
a2b6)÷(-
ab3)2.
(1)(a+b)-4(2a-3b)+(3a-2b)
(2)(
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
分析:(1)先去括号,再合并同类项即可;
(2)先算乘方,再算除法即可.
(2)先算乘方,再算除法即可.
解答:解:(1)(a+b)-4(2a-3b)+(3a-2b)
=a+b-8a+12b+3a-2b
=-4a+11b;
(2)(
a4b7+
a3b8-
a2b6)÷(-
ab3)2
=(
a4b7+
a3b8-
a2b6)÷
a2b6
=3a2b+2ab2-1.
=a+b-8a+12b+3a-2b
=-4a+11b;
(2)(
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
=(
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
=3a2b+2ab2-1.
点评:本题考查了整式的混合运算,牢记运算法则及运算顺序是解题的关键.
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