题目内容
计算题:(1)|-3+1|-(+2);
(2)-
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
(3)(-
| 5 |
| 6 |
| 5 |
| 4 |
| 3 |
| 2 |
| 1 |
| 2 |
(4)-14-(-5
| 1 |
| 2 |
| 4 |
| 11 |
分析:(1)先去掉绝对值号,再进行有理数的加减运算;
(2)利用加法交换律、结合律运算;
(3)先算乘方再算乘除,把除法转换成乘法运算后再进行计算;
(4)根据有理数混合运算的顺序,先算乘方再算乘除最后算加减.
(2)利用加法交换律、结合律运算;
(3)先算乘方再算乘除,把除法转换成乘法运算后再进行计算;
(4)根据有理数混合运算的顺序,先算乘方再算乘除最后算加减.
解答:解:(1)|-3+1|-(+2)
=2-2
=0;
(2)-
+(-
)-(-
)-0.5
=(-
-
)+(
-
)
=-
-
=-
;
(3)(-
)÷(-
)×
-(-
)2
=(-
)×(-
)×
-
=1-
=
;
(4)-14-(-5
)×
+(-2)3
=-1+
×
-8
=-1+2-8
=-9+2
=-7.
=2-2
=0;
(2)-
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
=(-
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
| 1 |
| 2 |
=-
| 1 |
| 2 |
| 1 |
| 4 |
=-
| 3 |
| 4 |
(3)(-
| 5 |
| 6 |
| 5 |
| 4 |
| 3 |
| 2 |
| 1 |
| 2 |
=(-
| 5 |
| 6 |
| 4 |
| 5 |
| 3 |
| 2 |
| 1 |
| 4 |
=1-
| 1 |
| 4 |
=
| 3 |
| 4 |
(4)-14-(-5
| 1 |
| 2 |
| 4 |
| 11 |
=-1+
| 11 |
| 2 |
| 4 |
| 11 |
=-1+2-8
=-9+2
=-7.
点评:本题考查比较全面:有绝对值的性质、加法的交换结合律、有理数的混合运算,熟练掌握运算法则是解题的关键.
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