题目内容
化简求值:(
-
)÷
,且x=3-
.
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
| 2 |
分析:把括号内的分式分母进行因式分解并通分计算,然后把分式的除法运算转化为乘法运算,约分后把x的值代入计算即可得解.
解答:解:(
-
)÷
=[
-
]÷
=
×
=
×
=
,
当x=3-
时,
原式=
=
=
=
=
.
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
=[
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x-4 |
| x |
=
| (x+2)(x-2)-x(x-1) |
| x(x-2)2 |
| x |
| x-4 |
=
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
=
| 1 |
| (x-2)2 |
当x=3-
| 2 |
原式=
| 1 | ||
(3 -
|
=
| 1 | ||
(1-
|
=
| 1 | ||
3-
|
=
3+
| ||||
(3-
|
=
3+
| ||
| 7 |
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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