题目内容

计算:
(1)(-3)+6-(-1);
(2)(-
7
5
)×15÷(-3
1
2
)

(3)(-2)3-3×[(-4)2÷8-(3-5)]-22
(1)(-3)+6-(-1)
=-3+6+1
=4;

(2)(-
7
5
)×15÷(-3
1
2
)

=-
7
5
×15×(-
2
7
)  
=6;

(3)(-2)3-3×[(-4)2÷8-(3-5)]-22
=-8-3×[16÷8-(-2)]-4
=-8-3×[2+2]-4
=-8-3×4-4
=-24.
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