题目内容
先化简,再求值:| 1 |
| 2a |
| a2-1 |
| a2-2a+1 |
| a2+a |
| a2-2a+1 |
| 1 |
| 2 |
分析:先算除法,再通分,然后进行四则运算,最后将a=-
代入.
| 1 |
| 2 |
解答:解:原式=
-
•
=
-
=
=
.
∵a=-
,∴原式=
=
=-4.
| 1 |
| 2a |
| (a+1)(a-1) |
| (a-1)2 |
| (a-1)2 |
| a(a+1) |
=
| 1 |
| 2a |
| a-1 |
| a |
=
| 1-2a+2 |
| 2a |
=
| 3-2a |
| 2a |
∵a=-
| 1 |
| 2 |
| 3-2a |
| 2a |
3-2×(-
| ||
2×(-
|
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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