题目内容
计算:
(1)-3-[-5+(1-0.2×
)÷(-2)];
(2)[-3+(-5+|-4|)×(-
)]÷
÷(-
)3.
(1)-3-[-5+(1-0.2×
| 3 |
| 5 |
(2)[-3+(-5+|-4|)×(-
| 3 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
分析:(1)先算小括号内的乘法和把除法运算转化为乘法运算得到原式=-3-[-5+(1-
)×(-
)],再计算小括号内的减法得到原式=-3-[-5+
×(-
)],接着计算中括号内的乘法运算,然后去括号后进行加减运算即可;
(2)先进行乘方运算得到原式=[-3+(-5+4)×(-
)]×
÷(-
),再计算小括号和除法转化为乘法得到原式=(-3+
)×
×(-
),然后计算小括号的减法后约分即可.
| 3 |
| 25 |
| 1 |
| 2 |
| 22 |
| 25 |
| 1 |
| 2 |
(2)先进行乘方运算得到原式=[-3+(-5+4)×(-
| 3 |
| 2 |
| 3 |
| 2 |
| 27 |
| 8 |
| 3 |
| 2 |
| 3 |
| 2 |
| 8 |
| 27 |
解答:解:(1)原式=-3-[-5+(1-
)×(-
)]
=-3-[-5+
×(-
)]
=-3-(-5-
)
=-3+5+
=2
;
(2)原式=[-3+(-5+4)×(-
)]×
÷(-
)
=(-3+
)×
×(-
)
=-
×
×(-
)
=
.
| 3 |
| 25 |
| 1 |
| 2 |
=-3-[-5+
| 22 |
| 25 |
| 1 |
| 2 |
=-3-(-5-
| 11 |
| 25 |
=-3+5+
| 11 |
| 25 |
=2
| 11 |
| 25 |
(2)原式=[-3+(-5+4)×(-
| 3 |
| 2 |
| 3 |
| 2 |
| 27 |
| 8 |
=(-3+
| 3 |
| 2 |
| 3 |
| 2 |
| 8 |
| 27 |
=-
| 3 |
| 2 |
| 3 |
| 2 |
| 8 |
| 27 |
=
| 2 |
| 3 |
点评:本题考查了有理数的混合运算:先算乘方,再算乘除,然后进行加减运算;有括号先算括号.
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