题目内容
(1)计算:(-1)2008+
-|-cos45°|;
(2)先将(
-
)÷
化简,然后请你选一个自己喜欢的x值,求原式的值.
| 1 | ||
|
(2)先将(
| x2 |
| x+1 |
| 1 |
| x+1 |
| x-1 |
| x |
(1)原式=1+
| ||||
|
| ||
| 2 |
=1+
| ||
| 2 |
| ||
| 2 |
=1;
(2)原式=
| x2-1 |
| x+1 |
| x |
| x-1 |
=
| (x+1)(x-1) |
| x+1 |
| x |
| x-1 |
=x,
取x=10,则原式=10.
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题目内容
| 1 | ||
|
| x2 |
| x+1 |
| 1 |
| x+1 |
| x-1 |
| x |
| ||||
|
| ||
| 2 |
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| 2 |
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| 2 |
| x2-1 |
| x+1 |
| x |
| x-1 |
| (x+1)(x-1) |
| x+1 |
| x |
| x-1 |