题目内容
2005| 1 |
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| 3 |
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| 3 |
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分析:把带分数分解成整数和分数两部分,分别进行运算,再根据加法结合律,使运算更加简便.
解答:解:原式=(2005+
)-(2004+
)+(2003+
)-(2002+
)+…+(1+
)-
=[(2005-2004)+(2003-2002)+(2001-2000)+…+(3-2)+1]+(
-
)×
=1×
+
×1003
=
.
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| 2 |
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=[(2005-2004)+(2003-2002)+(2001-2000)+…+(3-2)+1]+(
| 1 |
| 2 |
| 1 |
| 3 |
| 2006 |
| 2 |
=1×
| 2006 |
| 2 |
| 1 |
| 6 |
=
| 7021 |
| 6 |
点评:把带分数分解成整数和分数两部分是简便运算的最好办法.
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