题目内容

(1)(-x-y)(x-y)+(x+y)2
(2)(2a6x3-9ax6)÷(3ax3);
(3)(2x-5)(2x+5)-(2x+1)(2x-3);
(4)(
1
4
a2b)•(-2ab2)2

(5)-23+8-1×(-1)3×(-
1
2
-2+7°;
(6)(2x-y+1)(2x+y-1);
(7)(-2xy2+
1
4
xy)÷(-
1
4
xy)

(8)(a+2)(a2+4)(a4+16)(a-2);
(9)(x-y)2(x2+y22(x+y)2
(10)(5m3n22•(-2m23•(-n34
(11)(π-3)0+(-0.125)2009×82009
(12)(2am-3bn)(3an+5bm);
(13)(
1
3
x+
3
4
y)(
1
3
x-
3
4
y)-(
1
3
x-
3
4
y)2
(14)(-2a2+3a)-(a2-2a+1);
(15)-2a(a2b+a-1)
(16)[x4y-2x2(x2-3xy2)]÷(-2x3
(17)(2m+n)(3n+1)
(18)1012
(19)199×201
(20)20082
(21)782
(22)(a+b+1)(a+b-1)
(23)(a-b)(a+b)(a2+b2
(24)(66x6y3-24x4y2+9x2y)÷(-3x2y).
分析:本题需先根据整式的混合运算顺序和法则以及乘法公式,分别进行计算,即可求出结果.
解答:解:(1)(-x-y)(x-y)+(x+y)2
=-x2+y2+x2+2xy+y2
=2y(y+x);
(2)(2a6x3-9ax6)÷(3ax3);
=
2
3
a5-3x3

(3)(2x-5)(2x+5)-(2x+1)(2x-3);
=4x2-25-4x2+4x+3,
=4x-22;
(4)(
1
4
a2b)•(-2ab2)2

=a4b5
(5)-23+8-1×(-1)3×(-
1
2
-2+7°;
=-8+
1
8
×(-1)×4+1

=-8-
1
2
+1

=-7
1
2

(6)(2x-y+1)(2x+y-1);
=4x2-4xy+y2-1;
(7)(-2xy2+
1
4
xy)÷(-
1
4
xy)

=8y-1;
(8)(a+2)(a2+4)(a4+16)(a-2);
=a8-256;
(9)(x-y)2(x2+y22(x+y)2
=x8-2x4y4+y8
(10)(5m3n22•(-2m23•(-n34
=25m6n4•(-8m6)•n12
=-200m12n16
(11)(π-3)0+(-0.125)2009×82009
=1+(-1)
=0;
(12)(2am-3bn)(3an+5bm);
=6am+n+10ambm-9anbn-15bm+n
(13)(
1
3
x+
3
4
y)(
1
3
x-
3
4
y)-(
1
3
x-
3
4
y)2
=
1
9
x2-
9
16
y2
-
1
9
x2-
9
16
y2
+
1
2
xy,
=-
9
8
y2+
1
2
xy;
(14)(-2a2+3a)-(a2-2a+1);
=-3a2+5a-1;
(15)-2a(a2b+a-1),
=-2a3b-2a2+2a;
(16)[x4y-2x2(x2-3xy2)]÷(-2x3
=-
1
2
xy
+x-3y2
(17)(2m+n)(3n+1)
=6mn+2m+3n2+n;
(18)1012
=(100+1)2
=10000+200+1,
=10201;
(19)199×201
=(200-1)(200+1)
=40000-1,
=39999;
(20)20082
=(2000+8)2
=4000000+32000+64,
=4032064;
(21)782
=(80-2)2
=6400-320+4,
=6084;
(22)(a+b+1)(a+b-1)
=(a+b)2-1,
=a2+2ab+b2-1,
(23)(a-b)(a+b)(a2+b2),
=a4-b4
(24)(66x6y3-24x4y2+9x2y)÷(-3x2y).
=-22x4y2+8x2y-3.
点评:本题主要考查了整式的混合运算,在解题时要根据整式的混合运算和法则分别进行计算是本题的关键.
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