题目内容
计算:
(1)(-3)2-
×[3×(-
)2-14]+8×[(
)2-(-
)3-1];
(2)[(1-
)2-(-1
)÷(-1
)]×(-1
)3.
(1)(-3)2-
| 3 |
| 5 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
(2)[(1-
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 8 |
| 1 |
| 2 |
(1)原式=9-
×(3×
-1)+8×(
+
-1)
=9-
×
+2+1-8
=4-
=3
;
(2)原式=[(
)2-
×
]×(-
)3
=(
-
)×(-
)
=
×(-
)-
×(-
)
=-
+5
=3
.
| 3 |
| 5 |
| 4 |
| 9 |
| 1 |
| 4 |
| 1 |
| 8 |
=9-
| 3 |
| 5 |
| 1 |
| 3 |
=4-
| 1 |
| 5 |
=3
| 4 |
| 5 |
(2)原式=[(
| 2 |
| 3 |
| 5 |
| 3 |
| 8 |
| 9 |
| 3 |
| 2 |
=(
| 4 |
| 9 |
| 40 |
| 27 |
| 27 |
| 8 |
=
| 4 |
| 9 |
| 27 |
| 8 |
| 40 |
| 27 |
| 27 |
| 8 |
=-
| 3 |
| 2 |
=3
| 1 |
| 2 |
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