题目内容
先化简,再求值:
÷
+
,其中x=
+1.
| x-3 |
| x2-1 |
| x2-2x-3 |
| x2+2x+1 |
| 1 |
| x-1 |
| 2 |
原式=
×
+
=
,
当x=
+1时,原式=
=
.
| x-3 |
| (x+1)(x-1) |
| (x+1)2 |
| (x+1)(x-3) |
| 1 |
| x-1 |
| 2 |
| x-1 |
当x=
| 2 |
| 2 | ||
|
| 2 |
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