题目内容
计算:
(1)(
)-1×(π-
)0-
(2)(
)2÷(
)
(3)
-
.
(1)(
| 1 |
| 3 |
| 2 |
| 9 |
(2)(
| b |
| 2a |
| -b |
| a |
(3)
| 1 |
| x-y |
| y |
| x2-xy |
分析:(1)分别根据0指数幂、负整数指数幂及数的开方法则计算出各数,再根据实数混合运算的法则进行计算即可;
(2)根据分式的乘法法则进行计算即可;
(3)先通分,再把分子相加减.
(2)根据分式的乘法法则进行计算即可;
(3)先通分,再把分子相加减.
解答:解:(1)原式=3×1-3
=3-3
=0;
(2)原式=
×(
)
=-
;
(3)原式=
-
=
=
.
=3-3
=0;
(2)原式=
| b2 |
| 4a2 |
| a |
| -b |
=-
| b |
| 4a |
(3)原式=
| x |
| x(x-y) |
| y |
| x(x-y) |
=
| x-y |
| x(x-y) |
=
| 1 |
| x |
点评:本题考查的是分式的混合运算,熟知分式混合运算的法则是解答此题的关键.
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