题目内容
求证:-3x2-x+1的值不大于
.
| 13 |
| 12 |
证明:原式=-3(x2+
x+
)+
+1=-3(x+
)2+
,
∵(x+
)2≥0,即-3(x+
)2≤0,
∴-3(x+
)2+
≤
,
则-3x2-x+1的值不大于
.
| 1 |
| 3 |
| 1 |
| 36 |
| 1 |
| 12 |
| 1 |
| 6 |
| 13 |
| 12 |
∵(x+
| 1 |
| 6 |
| 1 |
| 6 |
∴-3(x+
| 1 |
| 6 |
| 13 |
| 12 |
| 13 |
| 12 |
则-3x2-x+1的值不大于
| 13 |
| 12 |
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