题目内容
化简求值:2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)],其中x=
,y=-
.
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原式=2x2-2xy-6x2+9xy-2x2-2(2x2-xy+y2),
=2x2-2xy-6x2+9xy-2x2-4x2+2xy-2y2,
=-2x2+5xy+2y2,
当x=时,y=-
原式=-
.
=2x2-2xy-6x2+9xy-2x2-4x2+2xy-2y2,
=-2x2+5xy+2y2,
当x=时,y=-
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