题目内容
先化简,再求值:| x-4 |
| x-2 |
| 4 |
| x2-4x+4 |
| x |
| x-2 |
| 2 |
分析:这道求代数式值的题目,不应考虑把x的值直接代入,通常做法是先把代数式化简,然后再代入求值.
解答:解:原式=
+
×
,
=
+
,
=
+
,
=
,
=
;
当x=
时,原式=
=1-
.
| x-4 |
| x-2 |
| x-4 |
| (x-2)^2 |
| x-2 |
| x |
=
| x-4 |
| x-2 |
| 4 |
| x(x-2) |
=
| x(x-4) |
| x(x-2) |
| 4 |
| x(x-2) |
=
| (x-2)2 |
| x(x-2) |
=
| (x-2) |
| x |
当x=
| 2 |
| ||
| 2 |
| 2 |
点评:这是个分式除法与加法混合运算题,运算顺序是先做除法,做除法时要注意先把除法运算转化为乘法运算,而做乘法运算时要注意先把分子、分母能因式分解的先分解,然后约分;然后再做加法.化简后代数求值.
练习册系列答案
相关题目