题目内容
先化简,再求值| y+1 |
| 2x |
| 1 |
| x+y |
| x+y |
| 2x |
| 2 |
| 2 |
分析:本题须先对要求的式子进行整理,然后再把x\y的值代入即可求出正确结果.
解答:解:
-
(
-x-y)-1
=
-
[
-(x+y)]-1
=
-
+1-1
=
把x=1+
,y=1-
得:
原式=
=
| y+1 |
| 2x |
| 1 |
| x+y |
| x+y |
| 2x |
=
| y+1 |
| 2x |
| 1 |
| x+y |
| x+y |
| 2x |
=
| y+1 |
| 2x |
| 1 |
| 2x |
=
| y |
| 2x |
把x=1+
| 2 |
| 2 |
原式=
1-
| ||
2(1+
|
=
2
| ||
| 2 |
点评:本题主要考查了分式的化简求值,在解题时要注意先对要求的分式进行化简是本题的关键.
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