题目内容
将下列各式配方:
(1)x2-4x+( )=(x-____)2;
(2)x2+12x+( )=(x+____)2;
(3)x2-
x+( )=(x-____)2;
(4)x2+2
x+( )=(x+____)2.
(1)x2-4x+(
(2)x2+12x+(
(3)x2-
| 3 |
| 2 |
(4)x2+2
| 2 |
考点:解一元二次方程-配方法
专题:
分析:根据配方法是平方和加减积的2倍,可得答案.
解答:解:(1)(1)x2-4x+( 4)=(x-____)2;
(2)x2+12x+( 36)=(x+____)2;
(3)x2-
x+(
)=(x-____)2;
(4)x2+2
x+( 2)=(x+____)2;
故答案为:4,36,
,2.
(2)x2+12x+( 36)=(x+____)2;
(3)x2-
| 3 |
| 2 |
| 9 |
| 16 |
(4)x2+2
| 2 |
故答案为:4,36,
| 9 |
| 16 |
点评:本题考查了配方法,凑成平方和加减积的2倍是解题关键.
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