题目内容
(1)计算:
(2)分解因式:(x2+y2)2﹣4x2y2
(3)先化简再求值:8x2﹣(x﹣2)(3x+1)﹣2(x+1)(x﹣1),其中x=﹣2.
(2)分解因式:(x2+y2)2﹣4x2y2
(3)先化简再求值:8x2﹣(x﹣2)(3x+1)﹣2(x+1)(x﹣1),其中x=﹣2.
解:(1)
=9+1﹣5
=5
(2)(x2+y2)2﹣4x2y2
=(x2+y2+2xy)(x2+y2﹣2xy)
=(x+y)2(x﹣y)2
(3)8x2﹣(x﹣2)(3x+1)﹣2(x+1)(x﹣1)
=8x2﹣3x2+5x+2﹣2x2+2
=3x2+5x+4
当x=﹣2时,原式=6
故答案为5、(x+y)2(x﹣y)2、6.
=9+1﹣5
=5
(2)(x2+y2)2﹣4x2y2
=(x2+y2+2xy)(x2+y2﹣2xy)
=(x+y)2(x﹣y)2
(3)8x2﹣(x﹣2)(3x+1)﹣2(x+1)(x﹣1)
=8x2﹣3x2+5x+2﹣2x2+2
=3x2+5x+4
当x=﹣2时,原式=6
故答案为5、(x+y)2(x﹣y)2、6.
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